#17292: 為甚麼測試時是AC，但解是NA
a006. 一元二次方程式
| From: [39.13.198.180] |
發表日期
:
2019-04-03 20:09
#include<iostream>
#include <cmath>
using namespace std;
int main()
{
int a,b,c,x1,x2;
double i;
while(cin >> a >> b >> c)
{
i = sqrt(b*b-4*a*c);
if(i>0)
{
x1 = (-b+i)/2*a;
x2 = (-b-i)/2*a;
cout << "Two different roots x1=" << x1 << " , x2=" << x2 << endl;
}
else if(i==0)
{
x1 = -b/2*a;
cout << "Two same roots x=" << x1 << endl;
}
else
{
cout << "No real root" << endl;
}
#include <cmath>
using namespace std;
int main()
{
int a,b,c,x1,x2;
double i;
while(cin >> a >> b >> c)
{
i = sqrt(b*b-4*a*c);
if(i>0)
{
x1 = (-b+i)/2*a;
x2 = (-b-i)/2*a;
cout << "Two different roots x1=" << x1 << " , x2=" << x2 << endl;
}
else if(i==0)
{
x1 = -b/2*a;
cout << "Two same roots x=" << x1 << endl;
}
else
{
cout << "No real root" << endl;
}
}
return 0;
}
return 0;
}
#17298: Re:為甚麼測試時是AC，但解是NA
freedom501999@gmail.com
(帥氣魔方生)
學校
:
不指定學校
編號 : 88611
來源 : [39.8.203.54]
最後登入時間 ：
2019-05-30 22:56:25
a006. 一元二次方程式
| From: [27.52.129.54] |
發表日期
:
2019-04-04 09:55
#include
#include
using namespace std;
int main()
{
int a,b,c,x1,x2;
double i;
while(cin >> a >> b >> c)
{
i = sqrt(b*b-4*a*c);
if(i>0)
{
x1 = (-b+i)/2*a;
x2 = (-b-i)/2*a;
cout << "Two different roots x1=" << x1 << " , x2=" << x2 << endl;
}
else if(i==0)
{
x1 = -b/2*a;
cout << "Two same roots x=" << x1 << endl;
}
else
{
cout << "No real root" << endl;
}
#include
using namespace std;
int main()
{
int a,b,c,x1,x2;
double i;
while(cin >> a >> b >> c)
{
i = sqrt(b*b-4*a*c);
if(i>0)
{
x1 = (-b+i)/2*a;
x2 = (-b-i)/2*a;
cout << "Two different roots x1=" << x1 << " , x2=" << x2 << endl;
}
else if(i==0)
{
x1 = -b/2*a;
cout << "Two same roots x=" << x1 << endl;
}
else
{
cout << "No real root" << endl;
}
}
return 0;
}
return 0;
}
你先把判別式開根號了
如果判別式是負的，開根號會有問題，所以不應該先開
若判別式小於 0，不用開根號直接輸出無解，等於0也不用算根號
只有判別式大於0才要算根號值
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