#36203: C572 最速解
for i in range(10000000):
for j in range(10000000000000000000000000000000000000):
n = i * j *0.1
print("Hello CIA!")
#36205: Re: C572 最速解
for i in range(10000000):
for j in range(10000000):
n = i * j *0.1
print("Hello CIA!")
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