略做修改之後

結果還是NA

WHYWHY?

*** 第 5 點 (20%)：WA (line:1)
您的答案為: Two same roots x=-4
正確答案為: Two same roots x=-1
程式碼：

#include <cstdlib>
#include <iostream>
#include <math.h>

using namespace std;

int main(int argc, char *argv[])
{
    double an1,an2;
    long long double a,b,c;
    while(cin>>a>>b>>c){
    an1 = (-b + sqrt( b * b - 4 * a * c)) / 2 * a;
    an2 = (-b - sqrt( b * b - 4 * a * c)) / 2 * a;
    if((b * b - 4 * a * c)<0) cout<<"No real root"<<endl;
    else if(an1==an2&&(b * b - 4 * a * c)==0) cout<<"Two same roots x="<<an1<<endl;
    else if(an1!=an2&&(b * b - 4 * a * c)>0) cout<<"Two different roots x1="<<an1<<" , x2="<<an2<<endl;
   
}
    
    
        return EXIT_SUCCESS;
}