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編譯錯誤， 請檢查語法是否符合系統所支援的編譯器的要求。
錯誤訊息：
/tmp/code_45323.cpp: In function `int main(int, char**)':
/tmp/code_45323.cpp:41: error: call of overloaded `sqrt(int)' is ambiguous
/usr/include/bits/mathcalls.h:157: error: candidates are: double sqrt(double)
/usr/include/c++/3.3/cmath:550: error:                 long double
   std::sqrt(long double)
/usr/include/c++/3.3/cmath:546: error:                 float std::sqrt(float)
/tmp/code_45323.cpp:44: error: call of overloaded `sqrt(int)' is ambiguous
/usr/include/bits/mathcalls.h:157: error: candidates are: double sqrt(double)
/usr/include/c++/3.3/cmath:550: error:                 long double
   std::sqrt(long double)
/usr/include/c++/3.3/cmath:546: error:                 float std::sqrt(float)
/tmp/code_45323.cpp:47: error: call of overloaded `sqrt(int)' is ambiguous
/usr/include/bits/mathcalls.h:157: error: candidates are: double sqrt(double)
/usr/include/c++/3.3/cmath:550: error:                 long double
   std::sqrt(long double)
/usr/include/c++/3.3/cmath:546: error:                 float std::sqrt(float)
/tmp/code_45323.cpp:50: error: call of overloaded `sqrt(int)' is ambiguous
/usr/include/bits/mathcalls.h:157: error: candidates are: double sqrt(double)
/usr/include/c++/3.3/cmath:550: error:                 long double
   std::sqrt(long double)
/usr/include/c++/3.3/cmath:546: error:                 float std::sqrt(float) 

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1. #include <cstdlib>   
2. #include <iostream>   
3. #include <cmath>   
4.   
5. using namespace std;   
6.   
7. int f(char c){   
8.     if(c=='N' || c=='S' || c=='W' || c=='E'){   
9.         return 1;   
10.     }   
11.     else{   
12.         return 0;   
13.     }   
14. }   
15.   
16. int main(int argc, char *argv[])   
17. {   
18.     char a[300];   
19.     double N=0,S=0,W=0,E=0,ans;   
20.     int temp=0,T=0;   
21.     bool kk;   
22.     while(cin>>a){   
23.         if(a[0]=='E' && a[1]=='N' && a[2]=='D' && a[3]=='\0'){   
24.             break;   
25.         }   
26.         T++;   
27.         kk=false;   
28.         N=0;   
29.         S=0;   
30.         W=0;   
31.         E=0;   
32.         for(int i=0;i<strlen(a)-1;i++){   
33.             if(a[i]>='0' && a[i]<='9'){   
34.                 temp*=10;   
35.                 temp+=a[i]-'0';   
36.                 kk=true;   
37.             }   
38.             else if(kk==true){   
39.                 if(f(a[i+1])==1){   
40.                     if(a[i+1]=='N' || a[i]=='N' ){   
41.                         N+=temp/sqrt(2);   
42.                     }   
43.                     if(a[i+1]=='S' || a[i]=='S' ){   
44.                         S+=temp/sqrt(2);   
45.                     }   
46.                     if(a[i+1]=='W' || a[i]=='W' ){   
47.                         W+=temp/sqrt(2);   
48.                     }   
49.                     if(a[i+1]=='E' || a[i]=='E' ){   
50.                         E+=temp/sqrt(2);   
51.                     }   
52.                 }   
53.                 else{   
54.                     if(a[i]=='N'){   
55.                         N+=temp;   
56.                     }   
57.                     if(a[i]=='S'){   
58.                         S+=temp;   
59.                     }   
60.                     if(a[i]=='W'){   
61.                         W+=temp;   
62.                     }   
63.                     if(a[i]=='E'){   
64.                         E+=temp;   
65.                     }   
66.                 }   
67.                 kk=false;   
68.                 temp=0;   
69.             }   
70.         }   
71.         E-=W;   
72.         N-=S;   
73.         ans=E*E+N*N;   
74.         ans=sqrt(ans);   
75.         cout.precision(3);   
76.         if(T!=1){   
77.             cout<<endl;   
78.         }   
79.         cout<<"Map #"<<T<<endl;   
80.         cout<<"The treasure is located at ("<<fixed<<E<<","<<fixed<<N<<")."<<endl;   
81.         cout<<"The distance to the treasure is "<<fixed<<ans<<"."<<endl;   
82.     }   
83.     system("PAUSE");   
84.     return EXIT_SUCCESS;   
85. }  
    感謝幫看

 

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sqrt(2)請改成sqrt(2.0)或是sqrt((double)2)

另外system("pause")也請拿掉

 

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3QQ